Slopes
of Perpendicular Lines …
A
proof that
If you have wondered
WHY the slopes of perpendicular lines have to be negative reciprocals, here is
an answer. This proof uses the geometry
of the coordinate system (and lots of subscripts like the 1 and 2 above); the
property can also be proven with trigonometry.
First, let’s start with
a general picture of perpendicular lines.
The equation of the
lines are and
At the point where the
lines intersect, the y values are equal.
Since y1 = y2,
we know that
[This is very important
in the proof!!]
Since we are working
with slopes, we need a second point on each line.
Let’s find the y values
when the x-coordinate is (x+1). (We
could use any convenient value, like (x+2) or (x-1) …it’s just a bit simpler if
we use (x+1) in our work.)
(x+1,
m1x+m1+b1)
y1:
(x+1,
m2x+m2+b2)
y2:
Now we have two points on each line, three
points all together. What shape do
those points make?? A right triangle!!
hypotenuse
Here is a close-up of the right triangle
We need to write
expressions for the lengths of the two legs and
the length of the hypotenuse. This will be based on the distance
formula between two
points.
The top leg (from the
intersection to the next point on y1 ):
For the bottom
leg (from the intersection to the next point on y2 ):
For the hypotenuse:
In the third
step, we use the fact that the lines intersect – which means that m1x+b1
= m2x+b2. Since
these quantities are equal, subtracting them (m2x+b2 – m1x
- b1 ) gives zero – they cancel
out.
In the right triangle,
we apply the Pythagorean property – the sum of the squares of each leg equals
the square of the hypotenuse.
Leg˛
+ Leg˛ =
Hypotenuse˛
Subtract and from both sides. Divide both sides by -2 (a-b)˛=(a-b)(a-b) =a˛-2ab-b˛
There we go!! If the product of the slopes is –1, then
the slopes are negative reciprocals.
In other words, when
two lines are perpendicular, they form a right triangle. In order for the right triangle to follow the
Pythagorean property, the slopes have to be negative reciprocals.